(9x+4)(2x^2-9x-5)=0

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Solution for (9x+4)(2x^2-9x-5)=0 equation: 


Simplifying
(9x + 4)(2x2 + -9x + -5) = 0

Reorder the terms:
(4 + 9x)(2x2 + -9x + -5) = 0

Reorder the terms:
(4 + 9x)(-5 + -9x + 2x2) = 0

Multiply (4 + 9x) * (-5 + -9x + 2x2)
(4(-5 + -9x + 2x2) + 9x * (-5 + -9x + 2x2)) = 0
((-5 * 4 + -9x * 4 + 2x2 * 4) + 9x * (-5 + -9x + 2x2)) = 0
((-20 + -36x + 8x2) + 9x * (-5 + -9x + 2x2)) = 0
(-20 + -36x + 8x2 + (-5 * 9x + -9x * 9x + 2x2 * 9x)) = 0
(-20 + -36x + 8x2 + (-45x + -81x2 + 18x3)) = 0

Reorder the terms:
(-20 + -36x + -45x + 8x2 + -81x2 + 18x3) = 0

Combine like terms: -36x + -45x = -81x
(-20 + -81x + 8x2 + -81x2 + 18x3) = 0

Combine like terms: 8x2 + -81x2 = -73x2
(-20 + -81x + -73x2 + 18x3) = 0

Solving
-20 + -81x + -73x2 + 18x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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